London City in A Square MM

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London City in A Square MM

Post by cronus » Fri Jun 06, 2014 1:04 pm

If you modeled the city of London, say 50 miles by 50 given the outer reaches, down to a square millimeter how fine scaled would it be before atoms became a issue with scale? How many atoms to a brick for the sake of argument? or would bricks be impossible given the size of atoms in such a model?
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Re: London City in A Square MM

Post by rainbow » Fri Jun 06, 2014 2:17 pm

You would be punished for mixing imperial units with metric. :saijin:
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Re: London City in A Square MM

Post by mistermack » Fri Jun 06, 2014 2:18 pm

I don't know the answer, but you have to remember that an atom isn't the smallest that you can go.

It's nowhere near the smallest thing. In fact, atoms are almost all empty space. And then of course, when atoms break down, you can go much much smaller. Like in a neutron star, or more still, like in a black hole. And the ultimate compression is the entire universe, contained in a volume of a pinhead, just after the big bang.
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Re: London City in A Square MM

Post by cronus » Fri Jun 06, 2014 3:36 pm

mistermack wrote:I don't know the answer, but you have to remember that an atom isn't the smallest that you can go.

It's nowhere near the smallest thing. In fact, atoms are almost all empty space. And then of course, when atoms break down, you can go much much smaller. Like in a neutron star, or more still, like in a black hole. And the ultimate compression is the entire universe, contained in a volume of a pinhead, just after the big bang.
They're the smallest things that stay put long enough to build a model with. Try stacking up electrons? :coffee:
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Re: London City in A Square MM

Post by Calilasseia » Fri Jun 06, 2014 4:05 pm

Working this problem entirely in metric units, so as to please rainbow ... :mrgreen:

We'll take a circle of radius 50 Km as our working space, which gives us a diameter of 100 Km, which, when converted to imperial units, is approximately 62 miles. So this should be sufficient to apply to the problem.

So, we're shrinking everything within a 100 Km diameter circle down so that the entire circle is contained within a square millimetre. There are 1,000 millimetres in a metre, 1,000 metres in a kilometre, therefore our scale factor is 10-8. According to this document, a standard British house brick as the following dimensions:

Length: 225 mm
Width: 112.5 mm
Height: 75 mm

Taking the smallest of these dimensions, reducing 75 mm by a factor of 10-8 reduces the smallest dimension of a standard British house brick to 7.5 × 10-11 m.

At this point, we note that the typical value for the Van der Waals radius of atoms is around 1.5 × 10-10 m. Unfortunately, this means that on the modelling scale calculated above, house bricks end up being approximately half the size of a typical atom. Therefore on the scale proposed, it would be impossible to model individual bricks with any actual physical material.

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Re: London City in A Square MM

Post by mistermack » Fri Jun 06, 2014 4:23 pm

Scumple wrote:
mistermack wrote:I don't know the answer, but you have to remember that an atom isn't the smallest that you can go.

It's nowhere near the smallest thing. In fact, atoms are almost all empty space. And then of course, when atoms break down, you can go much much smaller. Like in a neutron star, or more still, like in a black hole. And the ultimate compression is the entire universe, contained in a volume of a pinhead, just after the big bang.
They're the smallest things that stay put long enough to build a model with. Try stacking up electrons? :coffee:
Maybe you could make it out of neutrons? So long as you made it in under fifteen minutes.
It could be like an ice-sculpture, as a temporary piece that starts melting as soon as you make it.
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Re: London City in A Square MM

Post by cronus » Fri Jun 06, 2014 4:27 pm

Could be done in 4 sq mm then? Interesting... :read:
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Re: London City in A Square MM

Post by mistermack » Fri Jun 06, 2014 5:23 pm

Scumple wrote:Could be done in 4 sq mm then? Interesting... :read:
Yeh. All you need now is a neutron 3d printer, and 3d version of Google Earth.
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Re: London City in A Square MM

Post by cronus » Fri Jun 06, 2014 5:31 pm

mistermack wrote:
Scumple wrote:Could be done in 4 sq mm then? Interesting... :read:
Yeh. All you need now is a neutron 3d printer, and 3d version of Google Earth.
So I've gotta wait another ten or fifteen years before I can begin? :tup:
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Re: London City in A Square MM

Post by mistermack » Fri Jun 06, 2014 5:56 pm

Scumple wrote:
mistermack wrote:
Scumple wrote:Could be done in 4 sq mm then? Interesting... :read:
Yeh. All you need now is a neutron 3d printer, and 3d version of Google Earth.
So I've gotta wait another ten or fifteen years before I can begin? :tup:
I think you'll find something to do, to fill in the time.

In any case, London will be under water in fifteen years time, when the ice-caps melt.
So it should get a little simpler.
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What's red and bad for your teeth?

Post by piscator » Fri Jun 06, 2014 7:44 pm

Calilasseia wrote:Working this problem entirely in metric units, so as to please rainbow ... :mrgreen:

We'll take a circle of radius 50 Km as our working space, which gives us a diameter of 100 Km, which, when converted to imperial units, is approximately 62 miles. So this should be sufficient to apply to the problem.

So, we're shrinking everything within a 100 Km diameter circle down so that the entire circle is contained within a square millimetre. There are 1,000 millimetres in a metre, 1,000 metres in a kilometre, therefore our scale factor is 10-8. According to this document, a standard British house brick as the following dimensions:

Length: 225 mm
Width: 112.5 mm
Height: 75 mm

Taking the smallest of these dimensions, reducing 75 mm by a factor of 10-8 reduces the smallest dimension of a standard British house brick to 7.5 × 10-11 m.

At this point, we note that the typical value for the Van der Waals radius of atoms is around 1.5 × 10-10 m. Unfortunately, this means that on the modelling scale calculated above, house bricks end up being approximately half the size of a typical atom. Therefore on the scale proposed, it would be impossible to model individual bricks with any actual physical material.


So change the scale. Do you think roads are drawn to scale on quad sheets?

Why arbitrarily decide on atoms when 8 photons can render a brick timelessly? :biggrin:

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Re: What's red and bad for your teeth?

Post by cronus » Fri Jun 06, 2014 8:42 pm

piscator wrote:
Calilasseia wrote:Working this problem entirely in metric units, so as to please rainbow ... :mrgreen:

We'll take a circle of radius 50 Km as our working space, which gives us a diameter of 100 Km, which, when converted to imperial units, is approximately 62 miles. So this should be sufficient to apply to the problem.

So, we're shrinking everything within a 100 Km diameter circle down so that the entire circle is contained within a square millimetre. There are 1,000 millimetres in a metre, 1,000 metres in a kilometre, therefore our scale factor is 10-8. According to this document, a standard British house brick as the following dimensions:

Length: 225 mm
Width: 112.5 mm
Height: 75 mm

Taking the smallest of these dimensions, reducing 75 mm by a factor of 10-8 reduces the smallest dimension of a standard British house brick to 7.5 × 10-11 m.

At this point, we note that the typical value for the Van der Waals radius of atoms is around 1.5 × 10-10 m. Unfortunately, this means that on the modelling scale calculated above, house bricks end up being approximately half the size of a typical atom. Therefore on the scale proposed, it would be impossible to model individual bricks with any actual physical material.


So change the scale. Do you think roads are drawn to scale on quad sheets?

Why arbitrarily decide on atoms when 8 photons can render a brick timelessly? :biggrin:
Photons in a render engine don't actually exist. They are called photons. Not really anything except mathematical notation.
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Re: What's red and bad for your teeth?

Post by piscator » Fri Jun 06, 2014 9:14 pm

Scumple wrote:
piscator wrote:
Calilasseia wrote:Working this problem entirely in metric units, so as to please rainbow ... :mrgreen:

We'll take a circle of radius 50 Km as our working space, which gives us a diameter of 100 Km, which, when converted to imperial units, is approximately 62 miles. So this should be sufficient to apply to the problem.

So, we're shrinking everything within a 100 Km diameter circle down so that the entire circle is contained within a square millimetre. There are 1,000 millimetres in a metre, 1,000 metres in a kilometre, therefore our scale factor is 10-8. According to this document, a standard British house brick as the following dimensions:

Length: 225 mm
Width: 112.5 mm
Height: 75 mm

Taking the smallest of these dimensions, reducing 75 mm by a factor of 10-8 reduces the smallest dimension of a standard British house brick to 7.5 × 10-11 m.

At this point, we note that the typical value for the Van der Waals radius of atoms is around 1.5 × 10-10 m. Unfortunately, this means that on the modelling scale calculated above, house bricks end up being approximately half the size of a typical atom. Therefore on the scale proposed, it would be impossible to model individual bricks with any actual physical material.


So change the scale. Do you think roads are drawn to scale on quad sheets?

Why arbitrarily decide on atoms when 8 photons can render a brick timelessly? :biggrin:
Photons in a render engine don't actually exist. They are called photons. Not really anything except mathematical notation.
They sound like "Points", or "Nodes", "Lines" or even "Polylines" - all dimensionless in at least 1 dimension. Rendering just fills spaces between dimensionless objects with various "textures", densities, and colors of scalable hatching, if my dim rememberings of paper space CAD renderings serve me.

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